Tutorial on color matching (Psych 221)
Class: Psych 221/EE 362 Tutorial: Color Matching on Displays Author: Wandell Purpose: Introduce phosphor SPDs, XYZ functions, gamma, matching calculations Date: 01.02.96 Duration: 45 minutes
Matlab 5: Checked 01.06.98 BW Matlab 7: Checked 01.06.06 GN/BW
This tutorial introduces several computational methods in color. These are:
* How to compute the XYZ values of a light source * How to set a monitor output to achieve these XYZ levels * How to manage the nonlinear relationship between frame buffer and emitted light output * How to compute and plot the xy chromaticity values of a display
We must measure the main functions that define the color properties of any display: these are the phosphor spectral power distributions (SPDs). We measure these functions using a spectral radiometer, a device that measures the power per nanometer emitted by the display.
The spectral power distributions of a monitor in my lab, measured when the monitor display intensity was set to full value, are stored in columns of the matrix called "phosphors". This matrix is stored in the data file below
% Read in a display d = displayCreate('CRT-Dell'); phosphors = displayGet(d,'spd'); wavelength = displayGet(d,'wave'); % Plot the display phosphors vcNewGraphWin plot(wavelength,phosphors(:,1),'r-', ... wavelength,phosphors(:,2), 'g-',... wavelength,phosphors(:,3),'b-') xlabel('Wavelength (nm)'), ylabel('Intensity') title('Spectral Power Distribution of Example CRT'); set(gca,'xlim',[350 750]), grid on % To measure the XYZ values of these phosphors, we load in the xbar,ybar, % zbar functions defined by the CIE. These are also stored in the columns % of a matrix, called xyz. Because these functions are so widely used, % they are stored in the main toolbox area. vcNewGraphWin XYZ = ieReadSpectra('XYZ',wavelength); plot(wavelength, XYZ(:,1:3)); xlabel('Wavelength (nm)'), ylabel('Responsivity') legend('xbar','ybar','zbar'); title('CIE XYZ Functions'); set(gca,'xlim',[350 750]), grid on % To compute the (X,Y,Z) values of each of the phosphors by multiplying the % phosphor matrix times the xyz matrix. Notice that the phosphors are in % the columns of the matrix on the right, and the xbar,ybar,zbar functions % are in the rows of the matrix on the left. maxXYZ = XYZ'*phosphors % This calculation doesn't take into account the proper constants and % details of the formula. There is a routine that manages that for you. maxXYZ = ieXYZFromEnergy(phosphors',wavelength(:)); % The luminance of each phosphor is given by the Y values. The % maximum value is when the phosphors are set to maximum intensity. maxXYZ(2,:) % The total luminance the display can reach, with all three phosphors on, % is given by the sum of these three values, 100 cd/m^2 is a typical % luminance level for monitors. sum(maxXYZ(2,:))
ans = Figure (1: ISET GraphWin) with properties: Number: 1 Name: 'ISET GraphWin' Color: [1 1 1] Position: [0.0070 0.5500 0.2800 0.3600] Units: 'normalized' Use GET to show all properties ans = Figure (2: ISET GraphWin) with properties: Number: 2 Name: 'ISET GraphWin' Color: [1 1 1] Position: [0.0070 0.5500 0.2800 0.3600] Units: 'normalized' Use GET to show all properties maxXYZ = 0.0144 0.0117 0.0086 0.0079 0.0246 0.0044 0.0008 0.0040 0.0450 ans = 31.9501 67.1483 11.0284 ans = 110.1268
Suppose that you send a space ship to the surface of Mars. The spaceship sends back a measurement of a spectral power distribution. Let's load it up.
% We set up again, but this time we suppose the display is only calibrated % from 400 to 700 in 5 nm steps. wavelength = 400:5:700; d = displayCreate('CRT-Dell',wavelength); phosphors = displayGet(d,'spd'); XYZ = ieReadSpectra('XYZ',wavelength); marsSPD = ieReadSpectra('mars.mat',wavelength); clf,plot(wavelength,marsSPD,'r-') set(gca,'ylim',[0 1]) grid on, xlabel('wavelength (nm)'); ylabel('Intensity') title('Spectral Power Distribution measurement from Mars'); % Now, how do we set the monitor intensities so that what we see on a % display is a visual match to the spectrum measured on Mars? We use the % XYZ color-matching functions. First, measure the values for the Martian % spectrum marsXYZ = ieXYZFromEnergy(marsSPD',wavelength(:)); % Now, recall that the monitor color properties are determined by the % relative intensity of the outputs of the monitor phosphor SPDs. Suppose % these intensities are [r,g,b]'. Then the monitor output is % phosphors*[r,g,b]'. For example, when the red phosphor only is on the % spectrum is plot(wavelength, phosphors*[1 0 0]', 'r-'); xlabel('wavelength(nm)'); ylabel('Intensity') title('Energy (Red Phosphor)'); % When the red and blue are on, the output is plot(wavelength, phosphors*[1 0 1]','m-'); xlabel('wavelength(nm)'); ylabel('Intensity') title('Energy of Red and Blue Phosphors combined'); % To find the relationship between the [r,g,b] values and the monitor XYZ % outputs, we only need to multiply the output times the XYZ functions. % Hence, there is a matrix that maps the linear monitor intensities into % the XYZ values. This matrix is % RGB2XYZ = ieXYZFromEnergy(phosphors',wavelength)'; % Take a look at this matrix and think about its entries. Notice that the % first column contains the XYZ values associated with the red phosphor, % the middle with the green, and the third column is associated with the % blue. These values should make sense to you given the shapes of the XYZ % functions we have already plotted. % Now, to represent the Martian spectrum on our display, we need to compute % only one more thing. How do we set the [r,g,b] values when we know the % XYZ values of the spectrum? For this, we need a matrix that converts XYZ % to monitor linear gun intensities, the inverse of the matrix that we % have. So, we calculate this new matrix as XYZ2RGB = inv(RGB2XYZ) marsRGB = XYZ2RGB*marsXYZ' % This shows that the XYZ from the two energy values are the same XYZ. ieXYZFromEnergy((phosphors*marsRGB)',wavelength) ieXYZFromEnergy(marsSPD',wavelength) % The spectrum we should display, therefore, is equal to vcNewGraphWin; subplot(2,1,1) plot(wavelength,phosphors*marsRGB) title('Output SPD of the monitor'); set(gca,'ylim',[0 2]) xlabel('wavelength(nm)');ylabel('Energy (watts/nm/sr/m^2)') % This will be a visual match to the spectrum subplot(2,1,2) plot(wavelength,marsSPD); set(gca,'ylim',[0 2]) title('SPD of original martian image'); xlabel('wavelength(nm)');ylabel('Energy') % The principles are the same when we make a match on a normal monitor. % The only difference, which is reviewed below, is that the frame-buffer % entries and the intensity of the phosphor output are a nonlinearly % related. Hence, we must set the frame-buffer entries so that we obtain % the linear intensity outputs we have just calculated. This process is % called gamma correction.
Interpolating display SPD for consistency with new wave. XYZ2RGB = 0.0349 -0.0158 -0.0052 -0.0111 0.0201 0.0002 0.0004 -0.0016 0.0082 marsRGB = 279.6730 423.2905 130.1053 ans = 1.0e+04 * 2.7377 3.5904 2.1227 ans = 1.0e+04 * 2.7377 3.5904 2.1227
The relationship between the intensity emitted by a CRT phosphor and the frame-buffer value is generally a nonlinear function. An example of the function relating frame-buffer value to emitted light intensity is shown here:
load cMatch/monitorGam vcNewGraphWin; plot(1:256,monitorGam(:,1)), grid on xlabel('Frame buffer'); ylabel('Emitted intensity of red phoshor'); title('Display "Gamma" function') % This is called the "gamma" function of the display. The reason for this % title is that the function is roughly a simple power function and the % exponent has historically been called "gamma." Here is a comparison of % the gamma function of the red phosphor and a power function with an % exponent of 2.2, the most common value. frameBuffer = 1:256; pred = ((frameBuffer)/256).^(2.2); plot(frameBuffer,pred,'k-',frameBuffer,monitorGam(:,1),'r-') xlim([0 256]); xlabel('Frame buffer'); ylabel('Intensity'); title('Comparison of Power function and red phosphor emission') legend('y = x^2^.^2', 'Red phosphor','Location', 'NorthWest'); grid on % For this display, you can see that the fit is much better using a larger % exponent, namely frameBuffer = 1:256; pred = ((frameBuffer)/256).^(2.7); plot(frameBuffer,pred,'k-',frameBuffer,monitorGam(:,1),'r-') xlim([0 256]); xlabel('Frame buffer'); ylabel('Intensity'); title('Comparison of Power function and red phosphor emission') legend('y = x^2^.^7', 'Red phosphor','Location', 'NorthWest'); grid on % Recall that we measured the emitted intensity using the maximum % framebuffer value. This corresponds to the column entries in phosphor, % and these are the signals emitted when the relative intensity is one. % To specify the intensity of the emitted light for any given frame-buffer % level, we can use the simple gamma function. For example, the spectral % power distribution of the light emitted by the green phosphor at a frame % buffer level of 130 is emitted = phosphors(:,2)*monitorGam(130,2); plot(wavelength,emitted), grid on xlabel('Wavelength') ylabel('Intensity') title('SPD of Green Phosphor at fb = 130'); % Frequently, we are interested in how to set the frame-buffer % level in order to obtain a given linear output intensity. To % determine this, we must calculate the inverse of the "gamma" % function. If we have fit a simple polynomial to the gamma % function, then we can calculate the frame-buffer setting by % inverting the function. So that given a linear intensity, l, % we can calculate the frame-buffer value as frame-buffer = % l^(1/gamma). vcNewGraphWin; intensity = 0:.001:1; predFB = intensity.^(1/2.7); plot(intensity,predFB) xlabel('Intensity') ylabel('Frame buffer level') title('Gamma Function Inverse'); grid on % Another way to perform this calculation is by creating a % look-up table that inverts the gamma function. You should take % a look at the code in the function "mkInvGammaTable" to see how % Xuemei Zhang and I create inverse gamma look-up table % functions. To see the code enter "type mkInvGammaTable" invGamTable = mkInvGammaTable(monitorGam,1000); plot((1:1000)/1000,invGamTable), grid on xlabel('Relative intensity') ylabel('Frame buffer level') title('Inverse Gamma Table Values'); % (We make invGamTables with more than 8 bits of resolution % because some of the frame buffers we have in the lab are 10 % bits.) % To look up the frame buffer value that will produce a % particular linear intensity, then, we round the intensity to 1 % part in a thousand (because there are a 1000 levels in the % inverse table) and then use that as an index. For example, to % calculate the frame buffer values that generate linear % intensities of [.1 .3 .5 .7 .9] we calculate as intensity = (.1:.2:.9); intensityX = round(intensity*1000) fb = round(invGamTable(intensityX,1)) % Now, let's see how well we did. Here are the intensities we % will obtain with these frame buffer values. obtainedIntensity = monitorGam(fb,1) % We can plot the obtained and desired intensities in a graph % We are close, but because of the quantization of the device we % do not obtain the exact linear intensities. plot(intensity, obtainedIntensity, 'o', intensity, intensity,'-'), grid on axis equal, axis square, axis tight set(gca,'xtick',(0:.2:1),'ytick',(0:.2:1)) %identityLine = line([0 1],[0 1]); legend('Obtained Intensity', 'Ideal Intensity', 'Location', 'NorthWest'); title('Ideal vs Obtained Intensity');
Gamma table 1 NOT MONOTONIC. We are adjusting. Gamma table 2 NOT MONOTONIC. We are adjusting. Gamma table 3 NOT MONOTONIC. We are adjusting. intensityX = 100 300 500 700 900 fb = 115 163 196 222 244 obtainedIntensity = 0.0950 0.2935 0.4952 0.6907 0.8870
The monitor is also described in terms of several different chromaticity coordinate measurements, namely its "white point" and the gamut of colors that it can reach. The white point is the chromaticity coordinates of the display when all three phosphors are set to maximum intensity. These can be computed as
% We put the XYZ values into the columns (note the transpose) maxXYZ = ieXYZFromEnergy(phosphors',wavelength(:))'; whitePoint = chromaticity(sum(maxXYZ,2)')' % The (x,y) chromaticity coordinates of the phosphors can be % computed individually as xyMonitor = chromaticity(maxXYZ')' % We can build a graph describing the chromaticity coordinates of % the phosphors and the white point by first computing the xy % coordinates of the spectrum. Remember that the rows of xyz % contain the XYZ values of each spectral light. So, we can % compute the chromaticity of the spectral lights as xySpectrum = chromaticity(XYZ)'; % Modified 01-06-2005 PC xySpectrum = chromaticity(XYZ'); % Now, we plot these values and turn on hold. Any light is a % mixture of spectral lights, so these values define an outer % boundary for where any physical light can fall. plotSpectrumLocus; % Read this routine axis equal, axis square grid on, xlabel('x-chromaticity'), ylabel('y-chromaticity') title('Spectrum Locus (gamut of visible light)'); hold on % Overlay the xy coordinates of the three monitor phosphors on % top of the graph plot(xyMonitor(1,1),xyMonitor(2,1),'ro'); plot(xyMonitor(1,2),xyMonitor(2,2),'go'); plot(xyMonitor(1,3),xyMonitor(2,3),'bo'); % and place a patch over the region where sums of the phosphors % can fall. This is called the "gamut" of the display p = patch(xyMonitor(1,:), xyMonitor(2,:), [.5 .5 .5]); % Finally, add in the chromaticity coordinate of the white point % and label the axes. plot(whitePoint(1),whitePoint(2),'wo'); xlabel('x chromaticity'), ylabel('y chromaticity') hold off % Notice that the white point coordinates are not at the middle % of the gamut. The position of the white point depends on the % sum of the (X,Y,Z) values from each of the phosphors. These % are unequal, with the green and blue being the largest. Hence, % the white point is closer to these two corners of the gamut sum(maxXYZ)
whitePoint = 0.2849 0.3037 xyMonitor = 0.6237 0.2902 0.1490 0.3430 0.6095 0.0757 ans = 61.7836 110.1562 158.3428
% These ideas are all embedded in the existing plotting routines. But the % point of this script is to show you the ideas, not to plot the gamut. displayPlot(d,'gamut'); title(sprintf('%s gamut',displayGet(d,'name')));
USING THE COLOR MATCHING FUNCTIONS
Consider a color matching experiment using a CRT monitor with phosphor spectral power distributions (SPD) given by 'phosphors' in cMatch/monitor.mat
a) Using the CIE-XYZ method, calculate what phosphor intensities you will need to match a monochrome light at 550nm. What phosphor intensities are needed to match a monochrome light at 430nm?
b) Plot the SPD of the phosphors that would make this match. Why are these intensities not physically realizable?
c) If you wanted to perform an experiment to test the predicted match, what could you do to arrange the viewing conditions?
COLOR MONITOR CALIBRATION AND CHROMATICITY
a) Let the SPDs of the three phosphors of a color monitor be R, G, and B. Let the value of a pixel be written as a vector x = [r,g,b], where r, g, and b are between 0 and 1.
Write the matrix equation that expresses the SPD of a monitor pixel displaying the pixel x. (Ignore gamma correction)
b) How do the set of spectral power distributions emitted from a pixel compare with the spectral power distributions that are possible in the environment?
c) Typical monitors can modulate the linear phosphor intensity at 256 levels (8-bits). Suppose that you could modulate the phosphor intensities at 16-bit accuracy. Would this monitor produce better images? If you are not sure, then state what you need to know about the human visual system to decide whether the improvement is worthwhile.
d) Suppose that you are able to build a monitor with a fourth phosphor, not just the three that are usually built. In what sense would this monitor be better than a three-primary monitor? If you could set the x-y chromaticity of the phosphor, how would you design it to achieve the best monitor performance? You may want to sketch or plot a chromaticity diagram to show what you mean.
Suppose you are an LCD manufacturer, and you know that if you had an ideal LCD, each of the R,G,B color channels would emit light according to the SPD given in monitors.mat. We have already plotted the color gamut of such a monitor.
In a real LCD display, the LC gates are not able to block 100% of the light from the backlight. Suppose that due to such leakage, the contrast ratio between a fully black and fully white display is 100:1. Plot the gamut of colors for this display and explain what happens.